Converting 9 digit number into a string

2017 4 5
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更新时间：2021 8 17
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I have a (1675x 1) number matrix. Each numbers are 9 digit number. I want convert this no into string. When I am giving the num2str command it is giving me (1675 x 9) matrix, but I want to get a (1675 x 1) matrix. How can I do that?

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Joseph Cheng
Joseph Cheng 2017-4-5
why do you need it in a 1675x1 matrix? because that is not going to work with a string and matrix format as each digit is a index as a string. it can work as a cell array but i do not see any benefit for putting it in such a format.
Sadia
Sadia 2017-4-6
编辑：Walter Roberson 2017-4-6
I wanted to run the following code:
T = array2table (raw (2:end,[2,1,4,17,18]));
T.Properties.VariableNames = {'Station' 'Date' 'PM' 'Lat' 'Long'};
T2 = unstack(T, 'PM', 'Date', 'GroupingVariables', 'Station')
Then it is showing the following error
Error using tabular/unstack (line 212)
Unable to group rows using unique values of the table variable 'Station'. UNIQUE returned an error.
Error in PM25 (line 20)
T2 = unstack(T, 'PM', 'Date', 'GroupingVariables', 'Station')
Caused by:
Error using cell/unique (line 85)
Input A must be a cell array of character vectors.
That's why I wanted to convert this station from number to char. But my station values are 9 digit numbers and it is not giving me one character for one station.

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Walter Roberson
Walter Roberson 2017-4-5

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If you have R2016b or later, you can use compose()
Result = compose('%d', YourMatrix);
Otherwise you have to use a cell array if you want individual entries. For example,
Result = cellstr( int2str(YourMatrix) );

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Walter Roberson
Walter Roberson 2017-4-6
You should be using cell2table() rather than array2table() so that you can combine values of different types.

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