How to solve a boundary value problem (differential equations) which contains dependent variable values at the boundary??? The equation is like a integro-differential equation.

1 次查看（过去 30 天）
T S Singh
T S Singh 2017-4-11
评论： T S Singh 2017-4-12
(-iy+y'''')=(A+Bx)y'''(0)+(C+Dx)y''(0)
  1. Here A,B,C and D are constants.
  2. y'''(0) are the dependent variable 3rd order derivative at x=0.
  3. Like wise y''(0) is the 2nd oder derivative of y at x=0
  4. BCs y(0)=0, y'(0)=1, y''(1)=0 and y'''(1)=0

请先登录，再回答此问题。

采纳的回答

Torsten
Torsten 2017-4-12
编辑：Torsten 2017-4-12
Try "dsolve" on the problem
(-iy+y'''')=(A+Bx)*C2+(C+Dx)*C1
with boundary conditions
y(0)=0, y'(0)=1, y''(1)=0, y'''(1)=0, y''(0)=C1, y'''(0)=C2.
Best wishes
Torsten.
  7 个评论
显示 5更早的评论
Torsten
Torsten 2017-4-12
Since there is no integral involved in the differential equation, I don't see an obvious relation to integro-differential equations. But I might be wrong.
Best wishes
Torsten.
T S Singh
T S Singh 2017-4-12
Sorry I forgot to mention, the y'''(0) and y''(0) term in the differential equation was obtained from an integration expression, and these two terms remained because y'''(1) and y''(1) are zero because of the boundary conditions.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Calculus 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by