How can i create matrix automatically?

2017 4 13
2 个回答
回答已采纳
更新时间：2017 4 13
3 次查看（30 天）

0 个投票

Hi everbody
I should create a matrix by using number of element of any gap like as the example:
If gap has:
3 elements, matrix: [1 1 2]
4 elements, matrix: [1 1 2 2]
7 elements, matrix: [1 1 2 2 3 3 4] etc.
and matrix includes only 1 2 3 4 numbers, same numbers must be two side by side.
Is there any way for this operation?
Thanks...
Edit:
I have just created a loop for this operation:
for ...
elements=[1 1 2 2 3 3 4 4];
if numel(gap)<=numel(elements);
matrix=elements(1:numel(gap));
end
if numel(gap)>numel(elements);
diff=(numel(gap)-numel(elements))
matrix=[elements linspace(4,4,diff)]
end
end

请先登录，再回答此问题。

 采纳的回答

Stephen23
Stephen23 2017-4-13

1 个投票

>> fun = @(n)ceil((1:n)/2);
>> fun(3)
ans =
1 1 2
>> fun(4)
ans =
1 1 2 2
>> fun(7)
ans =
1 1 2 2 3 3 4

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Volkan Yangin
Volkan Yangin 2017-4-13
编辑：Volkan Yangin 2017-4-13
Thank you Stephen Cobeldick. By the time i have just created if-end loop for this operation and added under the your comment.

请先登录，再进行评论。

更多回答（1 个）

Volkan Yangin
Volkan Yangin 2017-4-13
编辑：Volkan Yangin 2017-4-13

0 个投票

for ...
elements=[1 1 2 2 3 3 4 4];
if numel(gap)<=numel(elements);
matrix=elements(1:numel(gap));
end
if numel(gap)>numel(elements);
diff=(numel(gap)-numel(elements))
matrix=[elements linspace(4,4,diff)]
end
end

类别

在 帮助中心 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by