accessing vector elements in random order and update new values

Question

jano satti 2017-4-14

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链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/335356-accessing-vector-elements-in-random-order-and-update-new-values

回答： KSSV 2017-4-17

A=[2 3 5]
B=[1 6 4]
X=[0 50 110 0 45]
Y=[250 0 0 35 0  120]

A and B are indices of X and Y respectively. I want to access in order (2,1)(3,6)(5,4) such that

if X(A)<Y(B) then X(A)-Y(B),(50-250) now X=[0 0 110 0 45] and Y=[200 0 0 35 0 120]
if X(A)>Y(B) then X(A)-Y(B),(110-120) now X=[0 0 0 0 45] and y=[200 0 0 35 0 10]
final answer is X=[0 0 0 0 10 ]| then Y=[200 0 0 10 0 10]

How can I do that? Thanks in advance.

for r=1:length(X)
if X(A)<Y(B)
          Ynew=minus(Y(B),X(A))
          Y(B)=Ynew
               X(A)=0
              Xnew=X(A)
              Anew=X+1
else  if X(A)>Y(B)
    for  r=1:length(b)
      Xnew=minus(X(A),Y(B))
         X(A)=Xnew
               Y(B)=0
              Ynew=Y(B)
               Ynew=Y+1
    end
  end    
  end 
  end

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Answer 1

KSSV 2017-4-17

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/335356-accessing-vector-elements-in-random-order-and-update-new-values#answer_263242

在 MATLAB Online 中打开

A=[2 3 5] ;
B=[1 6 4] ;
X=[0 50 110 0 45] ;
Y=[250 0 0 35 0  120] ;
X0=X ;
Y0=Y ;
for i = 1:length(A)
    if X(A(i))<Y(B(i))
        Y(B(i))=Y(B(i))-X(A(i)) ;
        X(A(i))=0 ;
    elseif  X(A(i))>Y(B(i))
        Y(B(i))=Y(B(i))-X(A(i)) ;
        X(A(i))=0 ;
    end
end