Using a for-loop with several input matrices
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I have several matrices that I want to run a for-loop through, and am not sure how to do this.
clc
clear all
TEST1 = [0 0 0 0];
TEST2 = [1, 1, 1, 1];
TEST3 = [235.0623 188.2428 44.9479 103.4551];
l = length(TEST3);
for k = 1:l
y(k) = 0;
if (k==1)
w(k) = 1/sqrt(l);
else
w(k) = sqrt(2/l);
end
for n = 1:l
y(k) = y(k)+TEST3(n)*cos(pi*(2*n-1)*(k-1)/(2*l));
end
y(k) = y(k)*w(k);
end
DCTTEST3 = (y)
My for-loop works well, and is currently programmed to use test3 matrix as the input, and show the corresponding matrix output.
Is it possible, without triplicating the code, to use this format but run the three test cases through it, and then have three output matrices? If it is, can you please show me how?
Thanks in advance! Chris
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回答(1 个)
Jan
2017-4-17
TestSet = {[0 0 0 0], ...
[1, 1, 1, 1], ...
[235.0623 188.2428 44.9479 103.4551]};
DCTTEST = cell(1, numel(TestSet)); % Pre-allocate
for iTest = 1:numel(TestSet)
Test = TestSet{iTest};
l = length(Test);
y = zeros(1, l); % Pre-allocate
w = zeros(1, l);
for k = 1:l
if (k==1)
w(k) = 1/sqrt(l);
else
w(k) = sqrt(2/l);
end
for n = 1:l
y(k) = y(k) + Test(n) * cos(pi * (2 * n-1) * (k-1) / (2*l));
end
y(k) = y(k)*w(k);
end
DCTTEST{iTest} = y;
end
2 个评论
Jan
2017-4-18
Use the debugger to see, what's going on. If this does not reveal the problem, post your code here.
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