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It only shows the else value if value of b crosses 15 even once.

1 次查看(过去 30 天)
b = AXIS(1:100,1) - KOTAK(1:100,1);
avg5 = zeros(5,1);
for k = 5:length(b)
avg5(k) = mean(b(k-4:k,1));
end
a = 0;
avg5 = [a;avg5];
avg5(numel(avg5),:) = [];
std5 = zeros(5,1);
for al = 5:length(b)
std5(al) = std(b(al-4:al,1));
end
% a = 0;
std5 = [a;std5];
std5(numel(std5),:) = [];
up5 = zeros(length(std5),1);
for d = 1 : length(std5)
if abs(b) < 14.5
up5(d) = std5*2 + avg5;
down5(d) = std5*(-2) + avg5;
else
up5(d) = std5*2 + avg5;
down5(d) = std5*(-2) + avg5;
end
end
It works well till up5 = zeros(length(std5,1));
  3 个评论

回答(1 个)

Steven Lord
Steven Lord 2017-4-19
That's the correct behavior. From the documentation for the if keyword: " if expression, statements, end evaluates an expression, and executes a group of statements when the expression is true. An expression is true when its result is nonempty and contains only nonzero elements (logical or real numeric). Otherwise, the expression is false. "
In your case, you probably want to use logical indexing instead.

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