Info

此问题已关闭。 请重新打开它进行编辑或回答。

It only shows the else value if value of b crosses 15 even once.

1 次查看（过去 30 天）
Adhish Aggarwal
Adhish Aggarwal 2017-4-19
关闭： MATLAB Answer Bot 2021-8-20
b = AXIS(1:100,1) - KOTAK(1:100,1);
avg5 = zeros(5,1);
for k = 5:length(b)
avg5(k) = mean(b(k-4:k,1));
end
a = 0;
avg5 = [a;avg5];
avg5(numel(avg5),:) = [];
std5 = zeros(5,1);
for al = 5:length(b)
std5(al) = std(b(al-4:al,1));
end
% a = 0;
std5 = [a;std5];
std5(numel(std5),:) = [];
up5 = zeros(length(std5),1);
for d = 1 : length(std5)
if abs(b) < 14.5
up5(d) = std5*2 + avg5;
down5(d) = std5*(-2) + avg5;
else
up5(d) = std5*2 + avg5;
down5(d) = std5*(-2) + avg5;
end
end
It works well till up5 = zeros(length(std5,1));
  3 个评论
显示 1更早的评论

此问题已关闭。

回答（1 个）

Steven Lord
Steven Lord 2017-4-19
That's the correct behavior. From the documentation for the if keyword: " if expression, statements, end evaluates an expression, and executes a group of statements when the expression is true. An expression is true when its result is nonempty and contains only nonzero elements (logical or real numeric). Otherwise, the expression is false. "
In your case, you probably want to use logical indexing instead.

此问题已关闭。

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by