my code is slower with a parfor loop

Question

emar 2017-4-21

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/336478-my-code-is-slower-with-a-parfor-loop

评论： Walter Roberson 2017-4-21

采纳的回答： Walter Roberson

在 MATLAB Online 中打开

Hello,

I ran this code in a computer with 44 workers. However, it's slower than the for version.

template=cell(31,1);
for i=1:31
   template{i}=rand(i+24);
end
parfor i=1:5
   img=rand(800,1280+i); % It's an other function that gives me the values of img ,here it's just an example
   tic
   cellfun (@(t) normxcorr2 ( t ,img),template,'UniformOutput',0);
   toc
end

As a result, elapsed time in each loop is approximately 18 s . When i change the parfor to for , the time elapsed is approximately 6.7 s in each loop .

Can you explain me why the parfor loop is slower than the for loop?

I checked Matlab documentation and also similar questions on Matlab answers, but it didn't help me.

Note : the total time of execution of the script is faster for the parfor version, i just want to understand why the function cellfun is 3 times slower in parallel version.

Thanks in advance

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Walter Roberson 2017-4-21

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/336478-my-code-is-slower-with-a-parfor-loop#answer_263872

normxcorr2 for large enough matrices probably ends up invoking the high performance libraries such as LINPACK or BLAS. Those high performance libraries are threaded and will use all available threads, even if you do not have the Parallel Computing Toolbox. When you use parfor then unless you are using R2017a or later and have specifically set the number of threads, then your parfor worker will only have a single thread available to it. That leads to the worker taking longer for that task.