Power conversion from mW to dBm?

Determine the power of a signal in dBm if absolute value is 100mW. Code:
u=100mW;
10*log10(u)+30
Could someone show the correct code for this conversion?

回答(1 个)

That seems to be correct according to the Wikipedia article on dBm.
An anonymous function version is:
dBm = @(mW) 10*log10(mW); % dBm As A Function Of Power In milliWatts
EDIT Corrected units.

6 个评论

Could you show an actual working code for finding the power of a signal in dBm if absolute value is 100mW?
If not, where can I find code sample for this conversion?
I have figured it out:
u=100; %mW
solution = 10*log10(u)+30
The inverse is also given in the Wikipedia article, although it wouldn’t be difficult to calculate:
dBm = @(mW) 10*log10(mW); % dBm As A Function Of Power In milliWatts
mW = @(dBm) 10.^(dBm/10); % mW As A Function Of dBm
NOTE According to the Wikipedia article, the units in my original Answer were in Watts, not mW, an error on my part in transcribing the wrong equation. I corrected it, and in this Comment. The units are now correct.
For units in Watts:
dBm = @(W) 30 + 10*log10(W); % dBm As A Function Of Power In Watts
W = @(dBm) 10.^((dBm-30)/10); % W As A Function Of Power In dBm
So, is my code from the second post correct?
u=100; %mW
solution = 10*log10(u)+30
I don't know if 'u' here is in 'mW' or in 'W'.
Here ‘u’ is in W, according to the Wikipedia article.
My apologies for the delay — serious computer problems. Firefox no longer works on my Win 8.1 machine, and routinely crashes it, destroying my MATLAB configuration files as well.

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