combine date & time

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Trader
Trader 2012-3-28
评论： sivakumar dumpala 2016-5-14
I've got an array that has 3 columns. Column 1 is a counter and I don't care about it, column 2 has the date in 'dd/mm/yy' format and column 3 has the time in 'HH:MM' format. I want to combine comlumn 2 and 3 so I can convert them to a serial format.
This is my code:
day = import1.textdata(2:end,2);
time = import1.textdata(2:end,3);
ns = arrayfun(@(n) datenum([day(n) time(n)],'dd/mm/yy HH:MM'),1:length(day),'UniformOutput', 0);
I am getting this error:
Error using ==> dtstr2dtnummx
Failed on converting date string to date number.
how can I resolve this? Is there an easier way to do this?
Thanks!
  1 个评论
sivakumar dumpala
sivakumar dumpala 2016-5-14
just concatenate those two columns.
time=[day,time]

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采纳的回答

Jan
Jan 2012-3-28
I guess, that your day and time are cell strings. If so, you can calculate the integer and fractional parts separately and add them:
ns = datenum(day) + datenum(time);
I cannot test this currently, perhaps you have to define the format:
ns = datenum(day, 'dd/mm/yy') + datenum(time, 'HH:MM') - datenum('00:00','HH:MM');
[EDITED]: Matt found out, that datenum uses the current year for the HH:MM format.
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Matt Tearle
Matt Tearle 2012-3-28
You can't get a date number from just HH:MM, though. Trying it, I get the appropriate time on Jan 1, 2012. I don't know how/why it defaults to that date -- it's probably deep in the documentation somewhere. So I suppose you could do:
datenum(day,'dd/mm/yy') + datenum(time, 'HH:MM') - datenum('00:00','HH:MM')
Jan
Jan 2012-3-28
Phew, another time where the very smart date function are too smart for me. Thanks Matt.

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更多回答（2 个）

Matt Tearle
Matt Tearle 2012-3-28
What class are day and time? If they are char arrays, then:
ns = datenum(strcat(day,32,time));
If they are cell arrays, then
ns = datenum(strcat(day,{' '},time));
EDIT TO ADD: As Jan points out, you don't even need the space if you specify the date format yourself, so:
ns = datenum(strcat(day,time),'dd/mm/yyHH:MM');
works for cells or chars.
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Jan
Jan 2012-3-28
You even do not need the space {' '}, when the format is defined accordingly as 'dd/mm/yyHH:MM'.
Matt Tearle
Matt Tearle 2012-3-28
Cunning!

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C.J. Harris
C.J. Harris 2012-3-28
Be careful when working with arrays in this manner. The terms day(n) and time(n) probably don't contain what you are expecting them to. Depending on what format your time and day array are in this might be a possible solution:
day = ['01/05/12'; '01/05/12'; '01/05/12'; '01/05/12'];
time = ['23:12'; '23:13'; '23:14'; '23:15'];
ns = arrayfun(@(n) datenum([day(n,:),' ',time(n,:)],'dd/mm/yy HH:MM'),1:size(day,1),'UniformOutput', 0);
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C.J. Harris
C.J. Harris 2012-3-28
My point was that if you are using 'arrayfun' then your dates and times are probably stored as an array. Indexing into the 'day' and 'time' array in the manner showed in your question will therefore only give you one character. That's why I changed the indexing and added a space in the solution I suggested.
Matt Tearle
Matt Tearle 2012-3-28
And if they are char arrays, then Chris's point about indexing also applies to what you tried with day(:). Linear indexing always goes down the columns of an array, because MATLAB stores data that way. Hence, if day is the char array that Chris gave in his answer, then day(:) gives '00001111////00005555...' (ie taking the characters one at a time, down each column in turn).

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