Two variables multiple constraints in calculus.

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Ema
Ema 2017-4-29
编辑： Walter Roberson 2017-5-3
<<se-mathworks-com-matlabcentral-answers-uploaded_files-76159-problem_4_5-jp.ng>>
clear all
a) -------------------------
r1 = linspace (1,4);
r2 = linspace (1,10);
C1 = 4+r1+r1.^2
C2 = 25./(1+(exp(1)).^(-r2+6))
Ctot = C1 + C2
plot(Ctot)
b) -------------------------
Dont know how to plot (Ctot) alongs the constraint 8r1+3r2=24
c) -------------------------
Think i got this one right
r0=[1,1];
Aeq=[8,3];
beq=24;
lb=[1,1];
ub=[4,10];
fun=@(r)4+r(1)+r(1)^2+25/(1+exp(-r(2)+6));
[r fval,EXITFLAG , OUTPUT] = fmincon(fun,r0,[],[],Aeq,beq,lb,ub);
X = fminsearch (fun, r0)
d)-------------------------
Struggling abit with this one.
i know that i can calculate second derivative with diff(Ctot,2) but dont know how to calcualte dCtot/dr(2)
e)-------------------------
I know how to calculate gradient with grad(Ctot = gradient(Ctot) but dont know how to calculate the gradient of the constraint in solvingpoint.
r
fval
OUTPUT.message
This is how far i've come. I know this problem should be really simple to solve, but i struggle. I have no clue about b, d, e part questions.

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采纳的回答

Will Nitsch
Will Nitsch 2017-5-3
For b):
R1 = (24-3.*linspace(1,10,1000))./8;
R2 = linspace(1,10,1000);
Ctot2 = @(r1,r2) C1(r1)+C2(r2); % I didn't spend too much time on this part but for whatever reason it didn't like 'Ctot = @(r) C1(r(1))+C2(r(2));'
figure
plot3(R1,R2,Ctot2(R1,R2))
I got the same answer as you for part c.
For d, just plug in that constraint for r1, 'r1 = (24-3*r2)/8' and differentiate.
Ctot3 = @(r2) 4+(24-3.*r2)./8+((24-3.*r2)./8).^2+25./(1+exp(-r2+6));
figure
plot(R2,Ctot3(R2))
hold on;
plot(R2(2:end),diff(Ctot3(R2))) % 1st derivative (R2 resized accordingly)
plot(R2(2:end-1),diff(Ctot3(R2),2)) % 2nd derivative (R2 resized accordingly, R2 may be a little off with this indexing but it was for dimensionality)
I'm not sure about part e, but perhaps with this other information you might be able to figure it out easier.

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