how to crop a binary image horizontally if vertical length exceeds a certain value?

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Sokhib Tukhtayev 2017-5-8

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https://ww2.mathworks.cn/matlabcentral/answers/339206-how-to-crop-a-binary-image-horizontally-if-vertical-length-exceeds-a-certain-value

评论： KSSV 2017-5-11

I have a couple of binary images depicting hand gestures. There are some side effects in those images, that is, images include arm part (down the wrist till elbow). Please view the images attached! I am going to crop this part according to some condition. Is there any way of writing a code for this?

For example: finding the vertical center of white region, or, finding the vertical length of the white region and cut out the bottom part percentage-wise?

Please note that the content of an image (hand) may have different verticality like in the 3rd attached image, so a suggested method should consider up to 40 % curvature as vertical.

Thank you for your ideas!

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KSSV 2017-5-8

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/339206-how-to-crop-a-binary-image-horizontally-if-vertical-length-exceeds-a-certain-value#answer_266023

在 MATLAB Online 中打开

I = imread('1.jpg') ;
[y,x] = find(I) ;
L = max(x)-min(x) ;
B = max(y)-min(y) ;
Icrop = imcrop(I,[min(x) min(y) L B]) ;

Crops only the region of interest.

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Sokhib Tukhtayev 2017-5-10

Sir, in this way I have to manually select the region, but still it is not what I want. It should automatically remove if the image exceeds a certain vertical length. The longer the image vertically is the more part from bottom should be cut.

Thank you anyway!

KSSV 2017-5-11

在 MATLAB Online 中打开

Try this:

I = imread('3.jpg') ;
imshow(I) ;
[y,x] = find(I) ;
x0 = min(x) ; x1 = max(x) ;
y0 = min(y) ; y1 = max(y) ;
%%Form a rectangle 
B = x1-x0 ;   % horizontal length 
L = y1-y0 ;   % vertical length
L0 = 200 ;  % specified length, change as you wish  
if L > L0
    dL = L-L0 ;
end
I(x0+dL:end,:) = 0 ;
imshow(I)

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