how to define the below function ?

2017 5 8
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更新时间：2017 5 8
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How to define the function f1= 2n<->2n+1 i.e it defines two transformations.
1. from value 2n to 2n+1.
2.from value 2n+1 to 2n.
Example. i.e let x= 30 (00011110). if we embed 0/1 then the result will be for 0= 30(00011110) i.e 2n for 1= 31(00011111) i.e 2n+1.
Thank you.

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回答（1 个）

Walter Roberson
Walter Roberson 2017-5-8

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@(v) v + 1 - 2*mod(v, 2)

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aditya sahu
aditya sahu 2017-5-8
Dear , Walter Roberson i could not understood your answer, Actually i need to write as function. would you please clarify more in detail about your answer . Thank you.
Walter Roberson
Walter Roberson 2017-5-8
function value = f1(x)
value = x + 1 - 2*mod(x, 2);

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