I am getting a 'Argument must contain a string' error.

Question

sivalogan satchithanandamoorthy 2017-5-8

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/339284-i-am-getting-a-argument-must-contain-a-string-error

评论： sivalogan satchithanandamoorthy 2017-5-8

[fileName,filePath] = uigetfile({'*.txt'},'Pick a file','MultiSelect','on')
pathToFile = fullfile(filePath,fileName)
x= size(pathToFile,2)
store=load(pathToFile(:,1));
prompt ='Please choose the Stress column';
stress=store(:,input(prompt));
prompt ='Please choose the strain column';
strain=store(:,input(prompt));

4 个评论
显示 2更早的评论隐藏 2更早的评论

Adam 2017-5-8

Where does 'str' come from?

sivalogan satchithanandamoorthy 2017-5-8

I want user to open multiple file. 'str' is basically a folder for one of the file.

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Walter Roberson 2017-5-8

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/339284-i-am-getting-a-argument-must-contain-a-string-error#answer_266108

在 MATLAB Online 中打开

store = load(pathToFile{1});

You have multiselect on and you are selecting multiple files, so pathToFile could be a cell array of strings. pathToFile(:,1) would then be a cell array of strings. When you use multiselect, you get a row vector cell array, so pathToFile(:,1) would be a 1 x 1 cell array of strings. You cannot load() using a cell array of strings: you have to load() a character vector such as pathToFile{1}

Caution: when multiselect is on, but the user only selects a single file, the first output is a char vector; if the user selects multiple files then the first output is a cell array of strings. You should not assume that the user definitely selected multiple files, so you should protect against the possibility:

[fileName,filePath] = uigetfile({'*.txt'},'Pick a file','MultiSelect','on');
if isnumeric(fileName); disp('Cancelled!'); return; end
fileName = cellstr(fileName);        %converts possible single string to cell array, leaves existing cell arrays the way they are.