How to plot the log scale?

1 次查看(过去 30 天)
If I have the following code:
syms t x ai di Kgr dc fc Rc fi_Ri Kei Kec fch_Rch_Nh0 fih_Rih_Nh0
g = @(t,x,ai,di,Kgr,dc,fc,Rc,fi_Ri,Kei,Kec,fch_Rch_Nh0,fih_Rih_Nh0)[Kgr*x(1)-dc*x(1)*x(2);ai*x(1)-di*x(2);fc*Rc*x(1)+fch_Rch_Nh0-Kec*x(3);fi_Ri*x(2)+fih_Rih_Nh0-Kei*x(4)]
ai=0.0474; di=0.1131; Kgr=5.78*10^(-3); dc=0.2*10^(-10); fc=0.1; Rc=4.5*10^(-5); fi_Ri=10.925*10^(-4); Kec=0.11; Kei=2.14;fch_Rch_Nh0=4.56*10^(1); fih_Rih_Nh0=7.16*10^(2) ;
cutoff1=34.11*3150; cutoff2=3.8*3150; threshold1= 1.5*3150; threshold2= 1*3150;
[t,xa] = ode45(@(t,x) g(t,x,ai,di,Kgr,dc,fc,Rc,fi_Ri,Kei,Kec,fch_Rch_Nh0,fih_Rih_Nh0),[0 4000],[1 1 0 0]);
figure
plot(t,xa(:,3),'r')
hline1=refline(0,cutoff1);
hline2=refline(0,threshold1);
set(hline1,'color','g','LineStyle','--')
set(hline2,'color','g','LineStyle','-')
hold on
plot(t,xa(:,4),'color','b')
hline3=refline(0,cutoff2);
hline4=refline(0,threshold2);
set(hline3,'color','b','LineStyle','--')
hline4.Color='m';
xlabel ('Time')
ylabel ('q_{PL}(t)')
title(['Tumor & Immune Biomarkers Shedding also by Healthy Cells'])
How can I plot t versus log x(3) and log x(4) instead of plot(t,xa(:,3))and plot(t,xa(:,4)) contained in the code? can I write plot(t,log (xa(:,3))) and plot((t,log (xa(:,4)))?
Thanks in advance.

采纳的回答

Star Strider
Star Strider 2017-5-9
‘can I write plot(t, log(xa(:,3))) and plot((t, log(xa(:,4)))?’
Yes, or you can use the semilogy plot:
semilogy(t, xa(:,3))
semilogy(t, xa(:,4))
  2 个评论
Esraa Abdelkhaleq
Thanks a lot. But I tried the two methods and got different results!!
Star Strider
Star Strider 2017-5-9
My pleasure.
The results appear to be different, because of the scaling on the y-axis. With your original code, the units will be in terms of ‘log(xa(:,c))’ (where ‘c’ is the column you choose). With semilogy, they will be in powers of 10.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Structures 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by