How to divide an area having multiple random points and work on each part separately?

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Asim Ismail 2017-5-10

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评论： Salma Hassan 2017-5-10

I have asked this question before but couldnt get a satisfactory answer, so let me explain it a bit more, maybe i can make myself more clear.

I have scattered 100 points randomly in a 100x100 plot and divided that area into 9 grids.

a=rand(2,100)*100;
scatter(a(1,:),a(2,:))
grid on
set(gca,'xtick',[0:33.33333:100])
set(gca,'ytick',[0:33.33333:100])

Now I want to get some idea that how can I make groups for each grid (having points within) so that I can work on each grid separately.

Any help will be appreciated, thanks a lot!

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Jan 2017-5-10

What exactly does "make groups" mean?

Asim Ismail 2017-5-10

编辑：Asim Ismail 2017-5-10

@ Jan, if we have random points scattered in a plot, then i want to find which grid have which points. The group means the group of points belong to a grid. For example

Grid1=[p1, p3, p4]

Grid2=[p6, p7, p8, p9] .... and so on

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采纳的回答

Jan 2017-5-10

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/339608-how-to-divide-an-area-having-multiple-random-points-and-work-on-each-part-separately#answer_266416

编辑：Jan 2017-5-10

在 MATLAB Online 中打开

Perhaps something like this simple loops:

a    = rand(2,100)*100;
grid = 0:33.33333:100;
Result = cell(numel(grid) - 1, numel(grid) - 1);
for i1 = 1:numel(grid) - 1
  for i2 = 1:numel(grid) - 1
    index = (grid(i1) <= a(1, :) & a(1, :) < grid(i1 + 1) & ...
             grid(i2) <= a(2, :) & a(2, :) < grid(i2 + 1));
    Result{i1, i2} = a(index);
  end
end