How can I use arithmetic operations (for C pointers) using coder.opaque types?

2017 5 12
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更新时间：2017 5 15
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Hello everyone,
I am into a project that uses coder.opaque to create char*, and I need memcpy to another another variable coder.opaque type, applying arithmetic operations to that "pointers".
Following I show you an example to explain what I am saying better:
first = coder.opaque('char*');
last = coder.opaque('char*');
def = coder.opaque('char*');
def = coder.ceval('(char*) malloc', 100);
% some operations %
memcpy(def, first+1, last-first); % Error. Expected either a <basic types>. Found a coder.opaque
How can I apply, or do the same, '+'/'-' operators to coder.opaque variables pointers, for move into the memory?
Regards,
Marcel

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0 个投票

Well,
I obtain a solution about this problem, but I am not very satisfied...., if anyone could do it better, please, share!.
In my case, I generate a C code, and with x=coder.opaque('char*', 'info+1'), when I use x on the parameters for coder.ceval() on the generated code it writes literally its value (info+1).
Regards,
Marcel

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