Why does inputparser instantiated within a class subfunction not use the default for the first optional argument?

2017 5 12
1 个回答
回答已采纳
更新时间：2017 5 15
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0 个投票

Hi there,
When I create an inputparser within a class method with a nested subfunction, it appears to not instantiate the first optional argument to the default value.
With the following test class:
classdef testclass < handle
properties
a
b
c
d
e
f
end
methods
function t = testclass(varargin)
p = inputParser;
addOptional(p,'a',1);
addOptional(p,'b',2);
addOptional(p,'c',3);
addOptional(p,'d',4);
addOptional(p,'e',5);
addOptional(p,'f',6);
parse(p,varargin{:});
t.a = p.Results.a;
t.b = p.Results.b;
t.c = p.Results.c;
t.d = p.Results.d;
t.e = p.Results.e;
t.f = p.Results.f;
end
function testfun(t,varargin)
testsubfun(t,varargin)
function testsubfun(t,varargin)
p = inputParser;
addOptional(p,'a',1);
addOptional(p,'b',2);
addOptional(p,'c',3);
addOptional(p,'d',4);
addOptional(p,'e',5);
addOptional(p,'f',6);
parse(p,varargin{:});
p.Results
end
end
end
end
If you call:
t=testclass('b',13,'c',14)
testfun(t,'b',13,'d',84)
I would expect the p.Results field to include the default value for the property 'a.' Instead, the entire varargin list is used as the value for that parameter. Is this a bug, or am I doing something wrong?
Thanks,
Lucas

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 采纳的回答

1 个投票

You are properly using the 'inputParser' class. However, when you are passing the arguments using 'varargin' from 'testfun' to 'testsubfun', MATLAB treats the 'varargin' as a variable (a 1x1 cell array that contains 1x4 cells). So, you need to pass the 'varargin' parameters as it is to the 'testsubfun' by changing the 'testsubfun' call to the following syntax:
>> testsubfun(t,varargin{:})

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