Varargin - mistake in my example

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Gennaro Arguzzi
Gennaro Arguzzi 2017-5-13
回答： Andrei Bobrov 2017-5-13
Hi everyone, I wrote the following function:
function [x] = ingressi_arbitrari(varargin)
x=0;
for k=1:nargin
x=x+1;
end
end
Why if I run a=ingressi_arbitrari([2 3]) in the command window, the result is a=1 instead of a=2 (I choose two input arguments)?
Thank you very much.

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采纳的回答

Walter Roberson
Walter Roberson 2017-5-13
You only have one input argument, that happens to be length 2. If you had
a=ingressi_arbitrari([2 3], [7; 1; 8; 5])
then you would have two input arguments, the first length 2 and the second length 4

更多回答（1 个）

Andrei Bobrov
Andrei Bobrov 2017-5-13
use:
ingressi_arbitrari(2,3)

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