how to exit a for loop if a condition is true?!

130 次查看（过去 30 天）
Ano
Ano 2017-5-16
评论： KSSV 2017-5-16
hello! I would like to exit a for lopp is a condition is true but my code doesn't seem to work, could you help me to figure out where is the problem?! Thank you best regards!
a= [ 1 2 3 5 8 6 8 8 2 8 2 8 2 8 2 1 nan 45 56 89];
for i= 1:length(a)
indx1 = find(isnan(a));
if ~isempty (indx1)
L = i ;
return
end
end
  2 个评论
Ano
Ano 2017-5-16
I need to get the index where the first nan is encountered and stop the loop as the main code should look for a critical point where the behavior starts to change

请先登录，再进行评论。

请先登录，再回答此问题。

回答（2 个）

KSSV
KSSV 2017-5-16
a= [ 1 2 3 5 8 6 8 8 2 8 2 8 2 8 2 1 nan 45 56 89];
for i= 1:length(a)
indx1 = find(isnan(a));
if ~isempty (indx1)
L = i ;
break
end
end
  2 个评论
Ano
Ano 2017-5-16
I have tried to use break but my L is always = 1, do you have any other suggestions ??!

请先登录，再进行评论。

Walter Roberson
Walter Roberson 2017-5-16
L = find(isnan(a), 1, 'first');
with no loop.
You are testing the same vector of values each time, all of a, so your result would always be either 1 or not found.

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by