How to extract a certain part from a string?
显示 更早的评论
Hi, I have a string variable with 9-digit value (not necessarily integer,could be capitalized-letter),
and I want to transform them into 8-digit value by removing the last digit value.
For example, my input will be some string as
'0036R3879' '0034658A6'
and respectively they should be transformed into
'0036R387' '0034658A'
such that the last digit is removed and the output is still a sting with 8 digit.
I don't know how to operate with string in this case, and the function 'strrep' seems not to work here.
Can someone familiar with string operation help me out?
Thank you!
采纳的回答
Guillaume
2017-5-17
Assuming R2016b or later:
extractBefore(yourstringarray, 9)
3 个评论
Star Strider
2017-5-18
According to the documentation, that syntax is new in R2017a.
Guillaume
2017-5-18
Hum, no. My documentation says that it was introduced in R2016b. The behaviour was changed in R2017a to return the same data type as the first input whereas in R2016b, it always returned string arrays.
Wei Feng Hsu
2017-5-18
更多回答（1 个）
Image Analyst
2017-5-17
Try this:
myStrings = string({'0036R3879'; '0034658A6'; '00300658A6'});
% Print to command window:
t = table(myStrings)
for row = 1 : size(t, 1)
% For every row...
oldString = t.myStrings{row};
t.myStrings{row} = oldString(1:end-1);
end
% Print to command window:
t
Hopefully it's rather self explanatory.
类别
在 帮助中心 和 File Exchange 中查找有关 Characters and Strings 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
