Compare matrices with datenum

1 次查看（过去 30 天）
David du Preez
David du Preez 2017-5-19
编辑： Andrei Bobrov 2017-5-19
Hi. I have 2 matrices. The first matrix A, (12x1) contains the monthly average values over 10 years. Row 1 is January, row 2 is February and so on. The second matrix B, is 8760x15. In column one there are hourly datenum values for an entire year and in column 15 there daily values. One value has been assigned for an entire day in column 15.
I want to remove an entire day if its value in column 15 is less than the corresponding monthly value in matrix A.
  2 个评论
Andrei Bobrov
Andrei Bobrov 2017-5-19
Please attach B - matrix here.
David du Preez
David du Preez 2017-5-19
Here is the correct B. It is just a sample of the matrix. Only has the 2 columns that relate to this question

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Andrei Bobrov
Andrei Bobrov 2017-5-19
编辑：Andrei Bobrov 2017-5-19
out = B(A(month(B(:,1))) <= B(:,end),:);

类别

在 Help Center 和 File Exchange 中查找有关 Dates and Time 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by