How to generate random integers from the uniform distribution between two numbers

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Zhan
Zhan 2017-5-21
评论： Stephen23 2017-5-22
Assume matrix A as follows:
A = [
810 840
840 870
870 900
900 930
930 960
];
For every row in matrix A,I want to generate random integers from the uniform distribution between column 1 and column 2. Also, these random numbers should be divided by 5 with decimal 0 (e.g. 810 (not 811)).
The output matrix size should be 5*1.
I think the right function is randi, but I don't know how to form it.
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Zhan
Zhan 2017-5-21
Thank @the cyclist.
Yes, the entire in A always multiples of 10. For the second part of your question, also, Yes. For example for the first row, 810 and/or 40 can be included. Thanks!
Stephen23
Stephen23 2017-5-22
@Zhan: you keep asking questions, but you have not accepted any of the answers to any of your questions. Accepting answers shows which answer solved your question, and is also an easy way for you to say "thank you" for our volunteer effort helping you.

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the cyclist
the cyclist 2017-5-21
编辑：the cyclist 2017-5-21
Under the assumption that you want to include the endpoints, and that the elements of A are evenly divisible by 5:
A = [
810 840
840 870
870 900
900 930
930 960
];
nrows = size(A,1);
r = zeros(nrows,1);
for nr = 1:nrows
r(nr) = 5*randi(A(nr,:)/5);
end

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Guillaume
Guillaume 2017-5-21
Simply loop over the rows:
result = zeros(size(A, 1), 1);
for row = 1:size(A, 1)
result(row) = randi(A(row));
end
I do not understand "these random numbers should be divided by 5 with decimal 0"
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Guillaume
Guillaume 2017-5-21
Oh! Well, in that case, simply divide the bounds by 5 and multiply the integer results by 5 afterward.

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