Using a loop to find out how long and how many terms

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So I have a problem that asks me to give a loop to see how long it takes to accumulate $1,000,000 in a bank account if you deposit $10,000 initially and $10,000 at the end of each year. Also the account pays 6% interest (0.06) each year.
Note:(The answer is 33 years, after 33 years the amount will be $1,041,800)
I've tried a while loop and can't arrive at that.
Please I need help!
Here is code I have so far:
money=10000; k=0; max=30;
while k > max
k=k+1;
money=money-(0.06*money);
if money > 1000000
break;
end
end
  3 个评论
Steven
Steven 2012-4-1
money=10000; k=0; max=30;
while k > max
k=k+1;
money=money-(0.06*money);
if money > 1000000
break;
end
end
I'm not getting any output for this. I don't know what to do.
Tyler Kelley
Tyler Kelley 2018-4-6
Balance = 10000; InterestRate = 1.06; Year = 0;
while Balance < 1000000
Balance = Balance*InterestRate + 10000;
Year = Year + 1;
end
disp(Year)

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采纳的回答

bym
bym 2012-4-1
Check your math
clc;clear
dep = 10000;
account = 10000;
year = 0;
while account < 1000000
year = year+1;
account = account*1.06 + dep;
end
sprintf('after %d years, the total is %7.0f dollars',year,account)

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