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how to split an array with a periodic set of elements as it reaches to the maximum elements?

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Joseph 2017-5-23

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https://ww2.mathworks.cn/matlabcentral/answers/341622-how-to-split-an-array-with-a-periodic-set-of-elements-as-it-reaches-to-the-maximum-elements

编辑： Andrei Bobrov 2017-5-25

采纳的回答： Andrei Bobrov

lets say i have an array with periodic set of elements such as below:

A=[2 2 2 3 3 4 4 5 5 5 1 1 1 2 2 2 2 3 3 4 4 4 4 5 5 1 1 2 3 3 4 4 4 5 5];

i want to split Array A in to 3 separate arrays(in this case) as it reach to element 5 as below:

B1=[2 2 2 3 3 4 4 5 5 5];

B2=[1 1 1 2 2 2 2 3 3 4 4 4 4 5 5];

B3=[1 1 2 3 3 4 4 4 5 5];

i greatly appreciate your help

thank you

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Andrei Bobrov 2017-5-24

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在 MATLAB Online 中打开

B = mat2cell(A(:)',1,diff(find([true,diff([A(:)'== 5,0]) == -1])));

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Joseph 2017-5-24

thank you for answer, however when i apply to my array, it gives me below error:

Input arguments, D1 through D2, must sum to each dimension of the input matrix size, [1 32025]

i should mention that my array size is A(32025,1);

Andrei Bobrov 2017-5-25

编辑：Andrei Bobrov 2017-5-25

Please attach your array A with size [32025 x 1] as mat-file.

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KSSV 2017-5-24

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https://ww2.mathworks.cn/matlabcentral/answers/341622-how-to-split-an-array-with-a-periodic-set-of-elements-as-it-reaches-to-the-maximum-elements#answer_268156

在 MATLAB Online 中打开

A=[2 2 2 3 3 4 4 5 5 5 1 1 1 2 2 2 2 3 3 4 4 4 4 5 5 1 1 2 3 3 4 4 4 5 5];
didx = diff(A==5) ;
idx = find(didx==-1) ;
idx = [0 idx length(A)] ;
N = length(idx)-1 ;
iwant = cell(N,1) ;
for i = 1:N
    iwant{i} = A(idx(i)+1:idx(i+1)) ;
end
celldisp(iwant)

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Joseph 2017-5-24

thanks for your help

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