Suppose a row vector x=1:8 and another vector of same size z=[1 1 0 1 1 0 1 1].I want to swap element in x according to element in z if z==1 then swap the postion of element of x else z==0 element of x should be in same position in vector.

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amit chatterjee 2017-5-24

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https://ww2.mathworks.cn/matlabcentral/answers/341663-suppose-a-row-vector-x-1-8-and-another-vector-of-same-size-z-1-1-0-1-1-0-1-1-i-want-to-swap-elemen

评论： Jan 2017-6-19

The number of swap should be equal to number of one in vector z divide by 2 if even ones else plus one divide by 2.The value of z change after each iteration so logic should be universal.

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amit chatterjee 2017-5-24

x=[1 2 3 4 5 6 7 8] and element of x randomly swap for example z=[1 1 0 1 1 1 1 0] then x[1] should swap because z[1] is equal to one and x[3] will have same element because z[3] is 0 and swapping is such that no element is repeated in x.e.g x[1] become x[2] and x[2] become x[4].

nitin jain 2017-6-10

The expected output should be like x=[4 6 3 1 7 2 5 8].whenever z==1 Swap the x element at that postion of x randomly while index of x correspond to x==0 should not be swapped.

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Jan 2017-5-24

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https://ww2.mathworks.cn/matlabcentral/answers/341663-suppose-a-row-vector-x-1-8-and-another-vector-of-same-size-z-1-1-0-1-1-0-1-1-i-want-to-swap-elemen#answer_268193

编辑：Jan 2017-5-24

在 MATLAB Online 中打开

Guessing that you want to swap the elements randomly:

x = rand(1, 8);  % Test data
z = [1 1 0 1 1 0 1 1];
xf   = x(z == 1);
n    = sum(z);          % Or: numel(xf)
p    = randperm(n, n);  % Faster than randperm(n)
x(z) = xf(p);