How to solve : Subscripted assignment dimension mismatch error

Dear guys I am new in MATLAB. It is a simple code which i make it. but i get this error message"Subscripted assignment dimension mismatch." I dont know whats the problem with that. would you please help me?
A=[]
A=randi(10,2,3)
for i=1:2
for j=1:3
if A(i,j)>3
A(i,j)='ok';
elseif A(i,j)==2
A(i,j)='no'
else
A(i,j)=' ';
end
end
end

1 个评论

A is a numeric array, which you then try to force non-scalar char vector into the elements of. It is not possible to put multiple array elements into one element of another array. If r and c are scalars, then:
X(r,c) = 1; % okay
X(r,c) = [1,2] % an error

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 采纳的回答

still I have a question.when I change the code to the following form it works too.why? the last code and new one, almost are the same. but why the original code in my question doesn't work but the modified version works? what is the difference between them? thanks in advance
the modifiied version is here A=[] A=randi(10,2,3) for i=1:2 for j=1:3 if A(i,j)>3 A(i,j)=0; elseif A(i,j)==2 A(i,j)=2 else A(i,j)=6; end end end

1 个评论

>> A=randi(10,2,3)
A =
9 2 7
10 10 1
>> A(1,1) = 2
A =
2 2 7
10 10 1
>> A(2,1) = 'no'
Assignment has more non-singleton rhs dimensions than non-singleton subscripts
>> double('no')
ans =
110 111
>>

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更多回答(1 个)

Use cell - array ( Aout) for output data in your function
A=randi(10,2,3);
Aout = cell(size(A);
for i=1:2
for j=1:3
if A(i,j)>3
Aout{i,j}='ok';
elseif A(i,j)==2
Aout{i,j}='no'
else
Aout{i,j}=' ';
end
end
end

1 个评论

thanks@Andrei Bobrov. It works for me. but still I have a question.when I change the code to the following form it works too.why? the last code and new one, almost are the same. but why the original code in my question doesn't work but the modified version works? what is the difference between them? thanks in advance
the modifiied version is here A=[] A=randi(10,2,3) for i=1:2 for j=1:3 if A(i,j)>3 A(i,j)=0; elseif A(i,j)==2 A(i,j)=2 else A(i,j)=6; end end end

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