How to solve : Subscripted assignment dimension mismatch error

Question

bahar kh 2017-5-26

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评论： Andrei Bobrov 2017-5-26

Dear guys I am new in MATLAB. It is a simple code which i make it. but i get this error message"Subscripted assignment dimension mismatch." I dont know whats the problem with that. would you please help me?

A=[]
A=randi(10,2,3)
for  i=1:2
    for j=1:3
        if A(i,j)>3
            A(i,j)='ok';
        elseif A(i,j)==2
            A(i,j)='no'
        else
            A(i,j)=' ';
        end
    end
end

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Stephen23 2017-5-26

编辑：Stephen23 2017-5-26

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A is a numeric array, which you then try to force non-scalar char vector into the elements of. It is not possible to put multiple array elements into one element of another array. If r and c are scalars, then:

X(r,c) = 1; % okay
X(r,c) = [1,2] % an error

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Answer 1

bahar kh 2017-5-26

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 still I have a question.when I change the code to the following form it works too.why? the last code and new one, almost are the same. but why the original code in my question doesn't work but the modified version works? what is the difference between them? thanks in advance

the modifiied version is here A=[] A=randi(10,2,3) for i=1:2 for j=1:3 if A(i,j)>3 A(i,j)=0; elseif A(i,j)==2 A(i,j)=2 else A(i,j)=6; end end end

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Andrei Bobrov 2017-5-26

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>> A=randi(10,2,3)
A =
     9     2     7
    10    10     1
>> A(1,1) = 2
A =
     2     2     7
    10    10     1
>> A(2,1) = 'no'
Assignment has more non-singleton rhs dimensions than non-singleton subscripts 
>> double('no')
ans =
   110   111
>>

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Answer 2

Andrei Bobrov 2017-5-26

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Use cell - array ( Aout) for output data in your function

A=randi(10,2,3);
Aout = cell(size(A);
for  i=1:2
    for j=1:3
        if A(i,j)>3
            Aout{i,j}='ok';
        elseif A(i,j)==2
            Aout{i,j}='no'
        else
            Aout{i,j}=' ';
        end
    end
end

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bahar kh 2017-5-26

编辑：bahar kh 2017-5-26

thanks@Andrei Bobrov. It works for me. but still I have a question.when I change the code to the following form it works too.why? the last code and new one, almost are the same. but why the original code in my question doesn't work but the modified version works? what is the difference between them? thanks in advance

the modifiied version is here A=[] A=randi(10,2,3) for i=1:2 for j=1:3 if A(i,j)>3 A(i,j)=0; elseif A(i,j)==2 A(i,j)=2 else A(i,j)=6; end end end

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