Variable 'D' is not fully defined on some execution paths. Why?
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Hello. I'm using the following code in embedded matlab in simulink. And I,m getting the message that Variable 'D' is not fully defined on some execution paths. And i don't know what is the problem in code.
function D = mpp(V,I,T)
Dinit = 0.7;
delD = 0.001;
Dmax = 0.9;
Dmin = 0.1;
persistent P0 V0 D0 n;
if isempty(P0)
P0 = 0;
V0 = 0;
n = 1;
D0 = Dinit;
end
P = V*I;
dP = P - P0;
dV = V - V0;
if(T>0.02*n)
n=n+1;
if(dP*dV > 0)
D = D0 - delD;
elseif(dP*dV < 0)
D = D0 + delD;
end
else
D = D0;
end
if D>=Dmax | D<=Dmin
D = D0;
end
V0 = V;
P0 = P;
D0 = D;
回答（1 个）
Walter Roberson
2017-6-2
if(dP*dV > 0)
D = D0 - delD;
elseif(dP*dV < 0)
D = D0 + delD;
end
does not assign to D if dp*dV == 0
4 个评论
Soham Delvadia
2017-6-2
Walter Roberson
2017-6-3
编辑：Walter Roberson
2017-6-3
What did you change the code to? The code you posted has a problem in the situation that dP == 0 or dV == 0.
小东 刘
2022-10-13
hello! now I have the same problem. How did you change it ?
Look at the simple example below. What does fun343107 do when x is exactly equal to 0? That behavior is undefined, so you'll receive a similar type of error as the original poster. To fix it, add code to handle the case where x is exactly equal to 0 in fun343107; that's the code that's commented out in the function.
Look for this same type of situation in your code.
y = fun343107(1)
y = fun343107(-1)
y = fun343107(0)
function y = fun343107(x)
if x > 0
y = 'positive';
elseif x < 0
y = 'negative';
% else
% y = 'zero';
end
end
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2017-6-2
2022-10-13
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