convert a nested struct in a matrix
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Hi, I have a nested struct
userTouristicTraj(1).touristicData(:).traj --> [1;1][1;1;1;1;1][1;1;1;1][1;1;1;1;1;1];[1;1];
userTouristicTraj(2).touristicData(:).traj --> [4;4][5;5]
userTouristicTraj(3).touristicData(:).traj --> [12;12;12;12;6][12;12]
and I want to trasform it in a matrix
A= [1 1 0 0 0 0; 1 1 1 1 1 0; 1 1 1 1 0 0; 1 1 1 1 1 1; 1 1 0 0 0 0; 4 4 0 0 0 0; 5 5 0 0 0 0; 12 12 12 12 6 0; 12 12 0 0 0 0]
I have try to use the functions struc2cell and cell2mat but the code doesn't run and maybe I have to use a different way
a=struct2cell(userTouristicTraj);
b=cell2mat(a);
Error using cell2mat (line 64)
The field names of each cell array element must be consistent and in consistent order.
Can you help me, please? thanks
采纳的回答
Assuming that all your structures have the same fields in all the substructures:
alltdata = [userTouristicTraj.touristicData]; %concatenate all touristicData into a single structure
alltraj = {alltdata.traj}; %and extract all traj into a cell array
maxlength = max(cellfun(@numel, alltraj));
alltraj = cellfun(@(v) [v.', zeros(1, maxlength - numel(v))], alltraj, 'UniformOutput', false) %pad as necessary
alltraj = vertcat(alltraj{:});
4 个评论
elisa ewin
2017-6-5
Guillaume
2017-6-5
Sorry, I missed that your vectors were column vectors (which you want transposed as row vectors).
I've fixed the code.
elisa ewin
2017-6-5
Guillaume
2017-6-5
Hopefully, fixed for good this time.
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