Hi,
You can resolve the first issue you are facing by using the following code snippet:
a=zeros(x,109); // x equals to the number of rows in temperature column of 'ca'
for i=1:123
a(:,i) = ca{1,i}(:,2)-ca{1,i+14}(:,2)
if (i+14)==123
break;
end
end
display(a);
Here, the loop starts with the first entry of the cell array 'ca' and accesses the temperature column(second column) of the array residing in that location 'ca{1,1}'. Then it finds the difference between the temperature of all the rows from that array and temperature of all the rows of the array which is 14 entries away from that location. The result of subtraction is getting stored in a (x * 109) size array where x is the number of rows in the temperature column of 'ca'. Also a check is implemented using 'if' to check if the maximum entry in 'ca' is reached or not.
The second issue what I understood is that the number of entries are different for every array. In this case you can fix a number of rows to subtract, not subtracting all the rows. If it does not affect your functionality. You can fix the row number as the number of rows of the array having the minimum among all.
