Subscripted assignment dimension mismatch in for loop
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Does anyone know what's wrong with this? I have tdatas and tissdatas with size (225x4). Every time I run this, I get the following error: Subscripted assignment dimension mismatch. Where am I wrong in this code? I just don't understand it or find it.
for i=1:length(tdatas(1,:))
fun = @(p,tdatas) objfunction(p,tdatas,tu);
z(i)=lsqcurvefit(fun,param0,tdatas(:,i),...
tissdatas(:,i),[0 0 0 0],[1 1 1 1],options);
end
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Star Strider
2017-6-11
You are estimating and returning 4 parameters, and assigning them to a 1 dimensional scalar. I do not know whether you are returning row or column vectors, so the easiest way is to use ‘z’ as a cell array:
z{i} = lsqcurvefit(fun,param0,tdatas(:,i),...
tissdatas(:,i),[0 0 0 0],[1 1 1 1],options);
Note the curly brackets ‘{}’ denoting cell array indexing.
4 个评论
Star Strider
2017-6-11
It should not return a scalar value in your code. (It would if you were only fitting one parameter.) The lsqcurvefit function estimates (and returns) the best-fit parameter vector for your model and data (and other outputs if you ask for them).
The lsqcurvefit function returns a vector because your anonymous function fits 4 parameters. There is nothing wrong with your code or with lsqcurvefit.
Please see the documentation on lsqcurvefit for an explanation of what it returns.
Star Strider
2017-6-11
Thank you!
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