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Subscripted assignment dimension mismatch in for loop

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Arbol
Arbol 2017-6-11
评论： Star Strider 2017-6-11
Does anyone know what's wrong with this? I have tdatas and tissdatas with size (225x4). Every time I run this, I get the following error: Subscripted assignment dimension mismatch. Where am I wrong in this code? I just don't understand it or find it.
for i=1:length(tdatas(1,:))
fun = @(p,tdatas) objfunction(p,tdatas,tu);
z(i)=lsqcurvefit(fun,param0,tdatas(:,i),...
tissdatas(:,i),[0 0 0 0],[1 1 1 1],options);
end
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Arbol
Arbol 2017-6-11
Or the following: In an assignment A(:) = B, the number of elements in A and B must be the same.

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Star Strider
Star Strider 2017-6-11
You are estimating and returning 4 parameters, and assigning them to a 1 dimensional scalar. I do not know whether you are returning row or column vectors, so the easiest way is to use ‘z’ as a cell array:
z{i} = lsqcurvefit(fun,param0,tdatas(:,i),...
tissdatas(:,i),[0 0 0 0],[1 1 1 1],options);
Note the curly brackets ‘{}’ denoting cell array indexing.
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Arbol
Arbol 2017-6-11
编辑：Arbol 2017-6-11
Oh sorry, yes, you are right! It will return 4 parameters. You are the best man! haha

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