Integral Problem

Question

0 个投票

I want to evaluate the integral of this function :

(cos(t^2)*sin(t)^2)^(1/2)

over the period -15*pi:50*pi

I am using these :

f=@(t) (cos(t.^2).*sin(t).^2).^(1/2);
quad(f,-15*pi,50*pi)

But i am getting warning:

Warning: Maximum function count exceeded; singularity likely.
> In quad at 110
In PPEL at 6
ans =
35.8252 +54.5673i

Most likely there is something stupid that i don't know about the theoretical part of the math :)

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Answer 1

Honglei Chen 2012-4-3

0 个投票

The function f is complex valued so this may be tricky. The following page may be helpful

Answer 2

Walter Roberson 2012-4-3

0 个投票

cos(t^2) oscillates fairly quickly near 50*pi . You are exceeding the maximum function count because of those fast oscillations.