Having the eigenvalue of my matrix (Hamiltonian), how can I get the eigenvector associated with it?
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Matt J
2017-6-13
V=null(A-eigenvalue*eye(size(A))
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John D'Errico
2017-6-13
A virtue of this solution is that if the eigenvalue has multiplicity greater than 1, then V will contain all the eigenvectors associated with that eigenvalue.
A = ones(3);
A has one eigenvalue of 3, but 0 is an eigenvalue, with multiplicity 2.
null(A-3*eye(size(A)))
ans =
-0.57735
-0.57735
-0.57735
null(A-0*eye(size(A)))
ans =
0 0.8165
-0.70711 -0.40825
0.70711 -0.40825
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