decimal increment inside a for loop
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Hi, I am trying to run a for loop as part of my code. I am trying to have 15 j values between z2 and z1 which are decimal numbers and change with every iteration. The error I am getting is "Subscript indices must either be real positive integers or logicals."I know I am getting the increments wrong but need some suggestions to solve the error.
for i = 1:1:49
X_even = [];
C_even = [];
P_even = [];
z1 = S0 - 2 * std(S) * sqrt(T - dt);
z2 = S0 + 2 * std(S) * sqrt(T - dt);
z = (z2-z1);
for j = z1:(z2-z1)/15:z2
X_even = [X_even ; X1(j,i)];
C_even = [C_even ; C1(j,i)];
P_even = [P_even ; P1(j,i)];
end
X1_even = [X1_even X_even];
C1_even = [C1_even C_even];
P1_even = [P1_even P_even];
end
采纳的回答
Star Strider
2017-6-13
You need to do something like this:
vj = z1:(z2-z1)/15:z2;
for j = 1:length(vj)
X_even = [X_even ; X1(j,i)];
C_even = [C_even ; C1(j,i)];
P_even = [P_even ; P1(j,i)];
end
If you are using ‘vj’ in calculations (although you do not seem to be in the code you posted), refer to fractional ‘j’ as ‘vj(j)’.
5 个评论
A Basu
2017-6-13
Star Strider
2017-6-13
As always, my pleasure!
Pablo Tejada Jr.
2020-4-14
Mr. Strider If I may ask a similar question. I created a "for Loop" that worked up to the point where I tried to modify within the "For Loop". If I may I am going to post my code. My error begins on my third for loop when I add .1 to my stress0.
formula Im using if it helps explain my question.clc
clear all
close all
E1=4000;
E2=5000;
Mu= 1.2*10^5;
stress0.norm = 800;
%The Following values are used to answer part E I
stress0.plus10 = 800+.1;
stress0.minus10 = 800-.1;
% The following loop generates points with E1 and E2.
for i=1:stress0.norm
strain.normal(i)=i/E1;
strain.E1plus10(i)=i/(E1+.1);
strain.E1minus10(i)=i/(E1-.1);
strain.E2plus10(i)=i/E1;
strain.E2minus10(i)=i/E1;
end
for i=stress0.norm:1500
strain.normal(i)=(i/E1)+((i-stress0.norm)/E2);
strain.E1plus10(i)=(i/E1+.1)+((i-stress0.norm)/E2);
strain.E1minus10(i)=(i/E1-.1)+((i-stress0.norm)/E2);
strain.E2plus10(i)=(i/E1)+((i-stress0.norm)/(E2+.1));
strain.E2minus10(i)=(i/E1)+((i-stress0.norm)/(E2-.1));
end
% Creating a another seperated loop for changes in stress0
for i=1:stress0.plus10
strain.stress0plus10(i)=i/E1; % This is where my error begins
end
for i=stress0.plus10;1500
strain.stressplus10(i)=(i/E1)+((i-stress0.plus10)/E2); % This is where my error begins
end
Steven Lord
2020-4-14
There's no such thing as element 799.9 of an array, like you're trying to assign to in this for loop.
for i=stress0.plus10;1500
strain.stressplus10(i)=(i/E1)+((i-stress0.plus10)/E2); % This is where my error begins
end
The semicolon in the line with your for loop should probably be a colon, but that won't save you because the first iteration through the loop you're trying to assign to strain.stressplus10(799.9).
Star Strider
2020-4-14
Als, that should be a new Question. It has nothing directly to do with the current thread.
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