how to find closest values in array)

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mona
mona 2017-6-17
回答： Image Analyst 2017-6-17
I want to find closest numbers in array as shown in example a=[4 7 8 9 10 11 20 23 26 27 28 29 30 60] output first group 7 8 9 10 11 second group 26 27 28 29 30
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mona
mona 2017-6-17
I need to automatically detect how many groups there are , each group membership is array and has values that difference between each number and next number is one. array is one dimension
Alex L
Alex L 2017-6-17
Is your array always going to be sorted? To refine your question: You are looking for groups of integers in your array that have an absolute difference of 1 to either the preceding or the following integer in the array?

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Image Analyst
Image Analyst 2017-6-17
If you have the Image Processing Toolbox, you can use bwlabel to give an "ID number" to each group that has the minimum spacing. Then you can extract each of those labeled groups one at a time and put into a cell array.
a=[4 7 8 9 10 11 20 23 26 27 28 29 30 60] % Original, easy case: separate groups
% a=[4 7 8 9 10 11 12 25 26 27 28 29 30 60] % Tricky test case: groups adjacent/touching
% a=[6 7 8 9 10 11 12 25 26 27 28 29 30 31] % Tricky test case: groups touch each other and ends
diffs = diff(a)
minSpacing = min(diffs)
binaryLabels = diffs == minSpacing
% Label the groups
labeledgroups = bwlabel(binaryLabels)
% Extract each group
for k = 1 : max(labeledgroups)
thisGroupsIndexes = find(labeledgroups == k);
% Tack one more.
thisGroupsIndexes = [thisGroupsIndexes, thisGroupsIndexes(end)+1]
% Extract these elements from the original "a" vector
result{k} = a(thisGroupsIndexes)
end

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