How to define a range of solutions and build a loop for a set of equations ?

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Emilie M 2017-6-18

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https://ww2.mathworks.cn/matlabcentral/answers/345250-how-to-define-a-range-of-solutions-and-build-a-loop-for-a-set-of-equations

评论： Emilie M 2017-6-19

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Hello,

I have 3 equations with 3 unknows: x, y, z.

The following code works

XA=0.4
XB=0.6
XC=0
IC50A=9456
IC50B=14.75
IC50C=7.602
syms x y z positive
eqn1 = XA.*x+(XA.*IC50A.*(y./IC50B+z./IC50C)) == x;
eqn2 = XB.*y+(XB.*IC50B.*(x./IC50A+z./IC50C)) == y;
eqn3 = XC.*z+(XC.*IC50C.*(x./IC50A+y./IC50B)) == z;
   sol = vpasolve(eqn1,eqn2,eqn3,x,y,z)
   s=[sol.x, sol.y, sol.z]

But, I have 2 questions:

1) How to define a loop in order to solve the equations for different set of XA, XB, XC: I wrote the code below, and I add the . before the * and /, but it does not work. Do you have any idea ?

   data=xlsread('valuefractions.xlsx');
   XA=data(:,1)
   XB=data(:,3)
   XC=data(:,2)

2) How to define a range of solutions for x, y and z ? I tried the code below, but it does not work too. Do you have any idea ?

setRange(x,19000,1000)
setRange(y,30,2)
setRange(z,15,1)

Thank you for your help.

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John D'Errico 2017-6-19

编辑：John D'Errico 2017-6-19

Where did you find setRange? Why do you think it applies here? If you are just making up the name of a function, then why do you think that you can just make up some function name and expect it to work? Note that I know of on;y one function named setrange, and I wrote it, for a completely different application.

Emilie M 2017-6-19