inputdlg string and convert variable to string

Question

Jonas K 2017-6-21

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评论： Stephen23 2017-6-22

Hello, I'm trying to achieve the following:

I need an input dialog box to open and type in a string. For example rock. Then I want rock to be a string (and not 'rock' with apostrophes) Because then rock can be recognized in the second line of code.

     image = inputdlg('Enter file name!')
     mask = tga_read_image([image '.mask.tga']);

I also tried to convert the variable image to a string, but that didn't work.

Can anybody help me? Cheers, Jonas.

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Answer 1

Stephen23 2017-6-21

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编辑：Stephen23 2017-6-21

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You should start by actually reading the documentation of the functions that you are using. If you had done this then you would have learned that inputdlg's "returned variable answer is a cell array containing one answer per text entry field, starting from the top of the dialog box."

So you can simply access the contents of that cell array, giving you:

   C = inputdlg('Enter file name!');
   mask = tga_read_image([C{1},'.mask.tga']);

Even better would be to use uigetfile or uiputfile.

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Jonas K 2017-6-22

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 filename = uigetfile('*.txt');
 [pathstr,filename,ext] = fileparts(filename);
 newname = sprintf('%s.mask.tga',filename)
 tga_read_image(newname);

got it, thank you! i need the reference for multiple file formats with all the same name (img1.txt img1.mask.tga img1.1.tga img1.2.tga and so on)

Stephen23 2017-6-22

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@Jonas K: good work. And for a final improvement you could also use fullfile to generate the complete filepath:

[filename,pathstr] = uigetfile('*.txt');
[~,filename] = fileparts(filename);
newname = sprintf('%s.mask.tga',filename);
newpath = fullfile(pathstr,newname);
tga_read_image(newpath);

The advantage is that the code will correctly process that file regardless of what folder it is in (i.e. your code and the files you are processing do not need to be all in the same folder).

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Answer 2

Star Strider 2017-6-21

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The single quotes will appear in the output because the value is a character array. It will work if you use cell array indexing to return the character array from the cell:

imgstr = inputdlg('Enter file name! ');
imgname = imgstr{:}
test_output = [imgname '.mask.tga']
imgname =
      'rock'
test_output =
      'rock.mask.tga'

Also, please do not use ‘image’ as a variable name. It is the name of a built-in MATLAB function that you may need later, and won’t be able to use because you will have ‘overshadowed’ it.

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Jonas K 2017-6-21

thank you, and i will. always learning:)

Star Strider 2017-6-21

My pleasure!

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Answer 3

Jonas K 2017-6-21

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I combined both answers now.

     img = uigetfile('./psmImages/*.txt');
     img = strrep(img,'.txt','')
     mask = tga_read_image([img '.mask.tga']);

Thanks everybody.

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Stephen23 2017-6-21

编辑：Stephen23 2017-6-21

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Using strrep to remove the file extension like that is not robust code. Consider this filename:

A.txt-2.txt

A much better way to remove the extension is to use the tool that is designed exactly for that purpose, which I showed you in a comment to my answer. Using the correct tool for a task makes your code clearer, less buggy, easier to understand,... and that is why any tool exists.

Also note that sprintf is preferred to string concatenation for generating filenames.

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