delete elements from a cell array

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elisa ewin
elisa ewin 2017-6-21
编辑： Andrei Bobrov 2017-6-22
Hi!
I have a cell array b (attached); in each cell of b I have an expression like this: 'Weather booming Chilli Relax https://t.co/pwp00Ndw3d' or expressions with @,#,$. I want to delete from these expressions all the characters like @,#,$ and the links like https://t.co/pwp00Ndw3d.
Example: if I have 'Weather booming @Chilli Relax# https://t.co/pwp00Ndw3d', I will want it becames 'Weather booming Chill Relax'
Can you help me? thanks
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elisa ewin
elisa ewin 2017-6-22
sorry, now I re-write the question
Jan
Jan 2017-6-22
编辑：Jan 2017-6-22
Weather booming Chilli Relax https://t.co/pwp00Ndw3d
This looks strange. It reminds me to Google: Britney Spears Instagram account used by hackers.
Perhaps I'm too distrustful, but I've modified the URL slightly to be sure. This does not change the core of the question or the answer. Sorry, these are hard times in the world wide web. Please do not take this personally.

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Andrei Bobrov
Andrei Bobrov 2017-6-22
regexprep(b,'[$#@]|\<https:/+\S*\>','')
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Andrei Bobrov
Andrei Bobrov 2017-6-22
编辑：Andrei Bobrov 2017-6-22
Hi Jan! Yes! "Russian rocket". :)
regexprep(b,'\<[^A-Za-z \?\,]|https:/+\S*\>','')

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Jan
Jan 2017-6-22
编辑：Jan 2017-6-22
S = 'Weather booming Chilli Relax https://t.co/pwp00Ndw3d';
C = strsplit(S, ' ');
C(contains(C, '/')) = []; % Or how you identify a link
for iC = 1:numel(C)
aC = C{iC};
C{iC} = aC(isstrprop(aC, 'alphanum'));
end
Result = sprintf('%s ', C{:});
Result(end) = [];
The command contains was introduced in R2016b. If you have an older version, use:
function Tf = contains(C, Patterm)
Tf = ~cellfun('isempty', strfind(C, Pattern));
end

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