What's the difference between the two pointer operators in the code gen?

Question

Rusczak 2017-7-4

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/347403-what-s-the-difference-between-the-two-pointer-operators-in-the-code-gen

评论： Walter Roberson 2017-7-5

采纳的回答： James Tursa

In code generation using Simulink coder the pointers can be used in two different ways:

(*ptr).variable or ptr->variable

What is the difference? When coder uses one or the other?

thanks

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

James Tursa 2017-7-5

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/347403-what-s-the-difference-between-the-two-pointer-operators-in-the-code-gen#answer_273002

I don't know why the Coder will produce one form vs the other form, but by definition in the C language they mean exactly the same thing to the C compiler.

3 个评论
显示 1更早的评论隐藏 1更早的评论

James Tursa 2017-7-5

编辑：James Tursa 2017-7-5

My first WAG is that maybe two different groups of people at TMW produced the Coder logic for the two different cases, and one group preferred the (*ptr).variable syntax while the other group preferred the ptr->variable syntax.

Walter Roberson 2017-7-5

In my experience (*ptr).variable becomes more probable with mechanical code generation that is traversing data structures looking for the correct field, whereas ptr->variable is more probable when you already know you are at the correct location. They mean the same, but when you are doing mechanical code generation you tend to be thinking of "current location" as an emphasis that tends to lead more to *ptr syntax.

请先登录，再进行评论。