What's the difference between the two pointer operators in the code gen?
2 次查看(过去 30 天)
显示 更早的评论
In code generation using Simulink coder the pointers can be used in two different ways:
(*ptr).variable or ptr->variable
What is the difference? When coder uses one or the other?
thanks
0 个评论
采纳的回答
James Tursa
2017-7-5
I don't know why the Coder will produce one form vs the other form, but by definition in the C language they mean exactly the same thing to the C compiler.
3 个评论
James Tursa
2017-7-5
编辑:James Tursa
2017-7-5
My first WAG is that maybe two different groups of people at TMW produced the Coder logic for the two different cases, and one group preferred the (*ptr).variable syntax while the other group preferred the ptr->variable syntax.
Walter Roberson
2017-7-5
In my experience (*ptr).variable becomes more probable with mechanical code generation that is traversing data structures looking for the correct field, whereas ptr->variable is more probable when you already know you are at the correct location. They mean the same, but when you are doing mechanical code generation you tend to be thinking of "current location" as an emphasis that tends to lead more to *ptr syntax.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Deployment, Integration, and Supported Hardware 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!