How to plot an hexagon or square spiral shape ?

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Zeinab Ahmadi93
Zeinab Ahmadi93 2017-7-8
编辑： DGM 2025-1-14
Hello I am trying to plot an spiral shape similar to one of the following figures(There is no difference, I need one of them, plooting in simple(solid) line is enough for me, I don't need markers on them) but I have no idea how to do it in matlab. Thanks in advance.

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采纳的回答

darova
darova 2020-6-14
try ths
t = 0:pi/2:100;
r = t.^2/100;
[x,y] = pol2cart(t,r);
plot(x,y)
pi/2 pi/4
  1 个评论
DGM
DGM 2025-1-14
编辑：DGM 2025-1-14
Ran in:
A bit of elaboration:
% parameters
nt = 15; % number of turns
ns = 6; % number of polygon sides
r0 = 1; % initial (maximum) radius
rp = 2; % controls the rate with which r decreases
th0 = 90; % initial angle
theta = (nt*2*pi:-2*pi/ns:0) + (pi*th0/180);
rho = r0*(theta/max(theta)).^rp;
[x,y] = pol2cart(theta,rho);
plot(x,y,'.-')
axis equal square

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更多回答（1 个）

jonatan
jonatan 2017-7-8
It is best to be solved in polar coordinates. For a simple square, you can show the relationship:
theta = 0:0.01:2*pi;
rho = min(abs(sec(t)), abs(csc(t)));
So if you want to create a spiral, you will need a small adjustment:
N = 10; %Number of spirals
theta = 0:0.01:2*pi*N;
rho = min(abs(sec(t)), abs(csc(t))) * theta;
You now can plot it using polarplot or convert it to Cartesian coordinates and using the regular plot function.

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