Setting limits using If statements

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JR
JR 2017-7-11
评论： KSSV 2017-7-11
Consider a random matrix:
A=[1.8 2.6 3.4 4.0 7.2]
[0.5 0.4 0.3 0.2 0.1]
I want to write a code that scans through A and does something if some conditions against parameters P1 and P2 are satisfied. Could somebody help me convert my pseudo code into a MATLAB script.
-----------------------------------------------------------------------------------
Pseudocode
-----------------------------------------------------------------------------------
P1=3.5;
P2=0.39;
for i=1 : (number of rows)
if an element A(i,:) is greater than or equal to P1
store all the elements from A(i,:) that come before P1;
but if an element A(i,:) is less than or equal to P2
store all the elements from A(i,:) that comes before P2;
end if
end for
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Expected Output:
StoredElements = [ 1.8 2.6 3.4 ]
[ 0.5 0.4 ]
-----------------------------------------------------------------------------------

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回答（1 个）

KSSV
KSSV 2017-7-11
This is pretty simple...you need not to run a loop. Read about find. http://in.mathworks.com/help/matlab/ref/find.html.
Also you can use the logical indexing. Ex..to get all the values in A which are less then or equal to p1..use
store = A(A(<=p1)
  2 个评论
JR
JR 2017-7-11
Thanks. It works if I write
store = A(A<P1)
but this will give me all the values in A that satiesfies the condition. What I want is to check it per row such that I tried writing my code this way:
store =A(1,:)(A(1,:)<P1)
But what I am getting is an error: Error: ()-indexing must appear last in an index expression.
KSSV
KSSV 2017-7-11
To run that in first row use:
A(1,A(1,:)<=P1)

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