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What (%.5g\n) does mean?

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hudof najeeb
hudof najeeb 2017-7-11
回答： Sebastian Castro 2017-7-11
disp(['PSNR ' num2str(measerr(CoverImg,s))])
[~, MSE] = measerr(CoverImg,s);
fprintf('MSE: %.5g\n', MSE)
the result is
PSNR 44.6192
MSE: 2.2447
I want MSE : 0.22447 What I must do?

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Sebastian Castro
Sebastian Castro 2017-7-11
The format string will indicate the display precision -- up to 5 decimal points.
What you're asking is to actually divide the value of MSE by 10... I am sure the following code will give you what you want, but you're manipulating your results and this is likely wrong.
fprintf('MSE: %.5g\n', MSE/10)
- Sebastian

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