Passing GPUArray to feval
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I have the following kernel
_global_ void func( float * arr, int N ) {
int rtid = blockDim.x * blockIdx.x + threadIdx.x;
if( rtid < N )
{
float* row = (float*)((char*)arr + rtid*N*sizeof(float) );
for (int c = 1; c < N; ++c)
{
//Manipulation
}
}
}
When I call the kernel from MATLAB using
gtm= parallel.gpu.GPUArray(ones(a,b,'double')); OR gtm= parallel.gpu.GPUArray(ones(1,b,'double'));
gtm=k.feval(gtm,b);
it is giving the following error:
Error using ==> feval
parallel.gpu.GPUArray must match the exact input type as specified on the kernel
prototype.
Error in ==> sameInit at 65 gtm=k.feval(gtm,b);
Can someone please tell me where am I going wrong.
Thanking You, Viharri P L V.
采纳的回答
Jill Reese
2012-4-9
You are creating gtm as a double, and trying to pass it as the first input to a kernel that expects a float. Try using this instead:
gtm = parallel.gpu.GPUArray.ones(a, b, 'single');
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2012-4-8
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