Unable to use mod function on cell array
显示 更早的评论
Say I have cell array A with size 10x10.
I want to perform a modulo on the 6th column of A, which is all numbers.
I have tried the following:
A(:, 6) = arrayfun(@(x) mod(x, 80), A(:, 3));
But then I get the error:
Undefined function 'mod' for input arguments of type 'cell'.
I then tried the following:
A(:,6) = mod(A(:,6), 80);
But I still get the same error. How do I do this?
I have also tried using cellfun:
A(:, 6) = cellfun(@(x) mod(x, 80), A(:, 3));
But then I get the following error:
Conversion to cell from int64 is not possible.
采纳的回答
dbmn
2017-7-19
you try to convert a int/double to a cell
% Create random Variable A
A=num2cell(rand(10,10));
% check if your cellfun is working
tmp = cellfun(@(x) mod(x, 80), A(:, 3));
% it is! no errors, great
% now lets assign that thing to your cell
% do a quick check about the types
class(tmp)
class(A(:,6))
% Uh oh, double and cell - that assignment wont work. We need to convert
% try
A(:,6) = num2cell(tmp);
% that works
And now that we know that it works, we try to do it nicely
A(:, 6) = num2cell(cellfun(@(x) mod(x, 80), A(:, 3)));
更多回答（1 个）
Guillaume
2017-7-19
Faster than using cellfun would be to convert the cell column to a matrix, perform the mod and convert back to a cell array:
A(:, 6) = num2cell(mod(cell2mat(A(:, 6)), 80));
On a large cell array, this probably is a lot faster.
类别
在 帮助中心 和 File Exchange 中查找有关 Cell Arrays 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
