How Can I randomly select 20% of my array elements AND save their indices (row,column) ?

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Omar Shehata
Omar Shehata 2017-7-19
评论： Jan 2017-7-19
I have a matrix A with n points.
A = [230,30,40,40,80;40 40 30 80 230;40 40 40 230 80]; n=numel(A);
How can i now randomly select a percentage of the points (example p=20% of n) ?
The output should be a new matrix with these random elements. AND another array that tells me "which" elements(row, column) were selected.
Any help appreciated :)

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采纳的回答

Jan
Jan 2017-7-19
编辑：Jan 2017-7-19
A = [230,30,40,40,80;40 40 30 80 230;40 40 40 230 80];
n = numel(A);
Index = randperm(numel(A), ceil(numel(A) * 0.20));
[Xp, Yp] = ind2sub(size(A), Index);
Selected = A(Index);
This chooses 20% of the values randomly and replies the values in Selected and the indices in Xp, Yp.
  2 个评论
Omar Shehata
Omar Shehata 2017-7-19
Thank you very much :)
what if I now want to have the "Selected" MATRIX in the same dimension as my data matrix "A". and all data which are not selected could be NaN or 0 then ?

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更多回答（1 个）

ES
ES 2017-7-19
A = [230,30,40,40,80;40 40 30 80 230;40 40 40 230 80];
n=numel(A);
B=reshape(A, 1, n); %1-D array
p = randperm(n);%random permutation of numbers till n
k = p(1:ceil(numel(p)/8));%Very poor algo for 1st to 20% of elements. You can improve here
C=B(p);%Target Matrix

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