From a string to function handle of a function handle

2 次查看(过去 30 天)
Hi,
Is it possible to transform a string into a function handle calling another function handle?
More specifically, consider the following simple example
func1=@(x)mean(x)
tmp='@(x)func1(x)+3'
we know that defining
func2=str2func(tmp)
does not work.
Is there any way to create a function handle using tmp that will work?
Thanks

采纳的回答

James Tursa
James Tursa 2017-7-19
func2 = eval(tmp);
  2 个评论
James Tursa
James Tursa 2017-7-20
Yep, agreed. If you don't know where that string is coming from and what could be in it or don't trust the source, then eval should probably be avoided.

请先登录,再进行评论。

更多回答(1 个)

Walter Roberson
Walter Roberson 2017-7-19
tmp='@(x)feval(evalin(''caller'',''func1''),x)+3'
  2 个评论
Patrick Mboma
Patrick Mboma 2017-7-19
Thanks Walter, I guess this would work but at the same time it looks like a very cumbersome way of going about it especially if you have long expressions.
Walter Roberson
Walter Roberson 2017-7-19
The basic issue is that str2func() is operating in a context outside your current workspace, so it does not have access to any variables in your workspace. evalin('caller') gives it that access. You would have the same difficulty with a plain variable:
>> A = 5
A =
5
>> tmp = '@(x) x+A'
tmp =
'@(x) x+A'
>> func2 = str2func(tmp)
func2 =
function_handle with value:
@(x)x+A
>> func2(7)
Undefined function or variable 'A'.
Error in @(x)x+A
str2func always does textual substitutions.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Function Handles 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by