Plotting a graph using indexed values

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Christine Nee
Christine Nee 2017-7-21
评论： Christine Nee 2017-7-24
I am trying to generate a plot. I use Max_value_Force and Min_value_Force to find the max and min values then I find where they are indexed. I then take the index and go back to my data and find when the force was min and max. After that I want to plot ALL the values between the max and min times as a plot with time (t) vs force (f). The reason why I am experimenting with time for now is because I am trying to figure out what full cycles look like on something I am analyzing. when I run this code I get an error.
[Max_value_force,I] = max(f(:))
Time_Max_Force = t(I)
[Min_value_force,I] = min(f(:))
Time_Min_Force = t(I)
plot(t(Time_Min_Force:Time_Max_Force),f(Time_Min_Force:Time_Max_Force))
"Warning: Integer operands are required for colon operator when used as index "
How do I get this to successfully generate a plot

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回答（1 个）

Jess Lovering
Jess Lovering 2017-7-21
It looks like you are trying to use the max and min values as the indices instead of the index values. See example:
[Max_value_force,maxI] = max(f(:))
Time_Max_Force = t(maxI)
[Min_value_force,minI] = min(f(:))
Time_Min_Force = t(minI)
plot(t(minI:maxI),f(minI:maxI))
  1 个评论
Christine Nee
Christine Nee 2017-7-24
Doesn't entirely work.
So here is my code. I am unable to plot nor put into array those values. I get an error with your revised code and my original code:
%Finding max values and creating a seperate array
[Max_Value_Force,maxI] = max(f(:))
Time_Max_Force = t(maxI)
%Max_Value_Force_Times_Array = t(I+1)
[Min_Value_Force,minI] = min(f(:))
Time_Min_Force = t(minI)
%Create the table with those values
%table has alternating values
Table = [Max_Value_Force Time_Max_Force; Min_Value_Force Time_Min_Force]
plot(t(minI:maxI),f(minI:maxI))
Any ideas on how to get this working as a plot and also on a table?

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