How to integrate the following function?

2017 7 22
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更新时间：2017 7 22
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mag = @(x)((1 - cos(x))./(1.25 + cos(x)).^1.5) With x ranging from 0 to 2*pi I used the command q = inetegral(mag, 0,2*pi) But I keep getting errors. Can somebody help me here?

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回答（1 个）

Star Strider
Star Strider 2017-7-22

0 个投票

If you spell integral correctly, it works:
mag = @(x)((1 - cos(x))./(1.25 + cos(x)).^1.5);
q = integral(mag, 0,2*pi);
q =
19.9868

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提问:

Shobhit
Shobhit
2017-7-22

回答：

Star Strider
Star Strider
2017-7-22

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