bidirection "FOR" loop counter
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Is there a way to make a FOR loop count in both ways positive and negative?!!.....the counter direction would be specified according to some condition for example:
l1=max(0,(i2-L));
b1=min(i2,(N/2-L));
for j1=l1:b1
In general; i want to give values for 'L' from 0 to 32, this will make l1>b1 for L from 0 to 16 and l1<b1 for L from 16 to 32
1 个评论
Image Analyst
2017-7-22
You can set
L = 0:32
but I don't know what i2 is, or what N is, or what values you expect j1 to take on. Please define those variables.
采纳的回答
Walter Roberson
2017-7-22
l1 = max(0,(i2-L));
b1 = min(i2,(N/2-L));
step = (l1 <= b1) * 2 - 1; %-1 if the condition is false, +1 if the condition is true
for j1 = l1 : step : b1
...
end
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