conversion of floating point to integer

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prateek
prateek 2012-4-10
My code to match a image with the images in database is :
img=handles.y;
mat=sum(img,1);
mat=mat(:);
k=zeros(30,1);
for i=1:30
str=strcat(int2str(i),'.pgm');
%concatenates two strings that form the name of the image
eval('img1=imread(str);');
mat1=sum(img1,1);
mat1=mat1(:);
k(i)=max(abs(normxcorr2(mat1,mat)));
end
%take maximum from matrix & store its value & position
vmax=max(k)
uval=int8(fix(vmax))
if uval>=1
figure(11);
op=imread('match.jpg');
imshow(op);
else
figure(12);
dp=imread('mismatch.jpg');
imshow(dp);
why int8(fix(x)) or int16(fix(x)) or int32(fix(x)) or int64(fix(x)) gives value 1 for vmax=1.0000 for few input images and gives value 0 for vmax=1.0000 for few other input images??

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回答（1 个）

Walter Roberson
Walter Roberson 2012-4-10
  3 个评论
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Walter Roberson
Walter Roberson 2012-4-10
1.0000 is not necessarily slightly greater than 1. When you use "format short" then MATLAB displays all numbers within 5/10000 of 1 as 1.0000 including exactly 1 itself.
Display
vmax - 1
to see the difference between vmax and 1 .

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